## Lunar and Solar DiametersOn this page we give a summary of how you, applying your own Let us take a look at our Pinhole Camera. Any such camera or the equivalent mirror method works on the geometrical principle of scaled triangles: Click on image to see larger version (28 K).As you may see on the very first drawing above, the large shaded triangle is equivalent to the small triangle. This gives us the following mathematical relations: During the 1996 October eclipse students from class 6A in Gymnasium beim Augarten, Vienna (Austria) did send these data:
Let us assume that during the August 1999 eclipse we will obtain results similar to what this group did back in October 1996. During the August 1999 Eclipse the lunar distance will officially be 373 200 km.
This means a
- Enter your own eclipse data, maybe including your own lunar distance and find your value for the
lunar diameter.
- Assuming we know the distance to the Sun as 1 AU = 149,600,000 km, now apply the same theory as
above to find the physical
diameter of the Sun!
Compare your value with the official value: 1,392,000 km. Show that the diameter of the Sun
is nearly 100 times larger than the Earth.
An accurate measurement of the apparent solar diameter can be achieved as follows:
Knowing that the Sun roughly moves 360 degrees in 24 hours (15 degrees in 1 hour) you can calculate the apparent size of the Sun. By repeating this timing several times an accurate value with no more than 1% deviation with a Pinhole Camera is possible! You can improve your result if you correct for the solar declination (on August 11 at 12 h UT: +15,3 degrees).
Applying some high school math (click for details) you convert the size of the projected solar image into a measure of the angular solar extension. Do this and compare with the official results given in the 2D Math Chapter. ## Please don't forget to send us a report, photos, results, etc.! |